What is the domain of (4x)/(x^2-9) ?

The domain of (4x)/(x^2-9) is x 3

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domain of (4x)/(x^2-9)

domain

\frac{4 x}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

e^{5 x + 3} + 2

f (x) = \frac{3}{x + 1 - 2}

f (x) = (e^{\frac{1}{x}})^{3}

f (x) = (9 - x^{2})^{2} - 9

2 arcsin (3 x + 1) - \frac{π}{2}

What is the domain of (4x)/(x^2-9) ?
The domain of (4x)/(x^2-9) is x<-3\lor-3<x<3\lor x>3