What is the domain of (sqrt(z+3))/(z-2) ?

The domain of (sqrt(z+3))/(z-2) is -3 2

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domain of (sqrt(z+3))/(z-2)

domain

\frac{z + 3}{z - 2}

- 3 \leq z < 2 or z > 2

Interval Notation

[- 3, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

z \geq - 3

Find undefined (singularity) points:

z = 2

Combine real regions and undefined points for final function domain

- 3 \leq z < 2 or z > 2

f (x) = \frac{- 4 x}{x ^{2} - 2}

f (x) = 5 - x g (x) = x^{2} - 4

y = x^{\frac{2}{3}}

f (x) = \frac{2 x - 7}{9 x + 2}

\frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

What is the domain of (sqrt(z+3))/(z-2) ?
The domain of (sqrt(z+3))/(z-2) is -3<= z<2\lor z>2