What is the domain of f(x)=sqrt(5-x)g(x)=sqrt(x^2-4) ?

The domain of f(x)=sqrt(5-x)g(x)=sqrt(x^2-4) is x = 2

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domain of f(x)=sqrt(5-x)g(x)=sqrt(x^2-4)

domain

f (x) = 5 - x g (x) = x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

y = x^{\frac{2}{3}}

f (x) = \frac{2 x - 7}{9 x + 2}

\frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

\frac{- x ^{2} + 7 x - 10}{x - 3}

f (x) = 1 - \frac{x ^{2}}{16}

What is the domain of f(x)=sqrt(5-x)g(x)=sqrt(x^2-4) ?
The domain of f(x)=sqrt(5-x)g(x)=sqrt(x^2-4) is x<=-2\lor x>= 2