What is the domain of f(x)=(x^2+3x-4)/(x^2-x-6) ?

The domain of f(x)=(x^2+3x-4)/(x^2-x-6) is x 3

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domain of f(x)=(x^2+3x-4)/(x^2-x-6)

domain

f (x) = \frac{x ^{2} + 3 x - 4}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

- 16 x^{2} - 49 x

- 6 x^{2} (5 x - 3)

f (x) = \frac{x ^{2}}{x ^{2} + x - 20}

f (x) = 1 + \frac{3}{2 x}

\frac{X - 16}{X - 81}

What is the domain of f(x)=(x^2+3x-4)/(x^2-x-6) ?
The domain of f(x)=(x^2+3x-4)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3