What is the domain of f(x)=(x-1)/(x^2+6x-16) ?

The domain of f(x)=(x-1)/(x^2+6x-16) is x 2

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domain of f(x)=(x-1)/(x^2+6x-16)

domain

f (x) = \frac{x - 1}{x ^{2} + 6 x - 16}

x < - 8 or - 8 < x < 2 or x > 2

Interval Notation

(- \infty, - 8) \cup (- 8, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 8

The function domain

x < - 8 or - 8 < x < 2 or x > 2

y = x - 2, x \geq 2

arccos (\frac{2 arcsin ( \frac{1}{4 x ^{2} - 1} )}{π})

f (x) = 84 x^{2} - x^{3}

\frac{\frac{8}{x + 6}}{\frac{7}{x}}

What is the domain of f(x)=(x-1)/(x^2+6x-16) ?
The domain of f(x)=(x-1)/(x^2+6x-16) is x<-8\lor-8<x<2\lor x>2