What is the domain of (2x+3)/(7x-5) ?

The domain of (2x+3)/(7x-5) is x 5/7

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domain of (2x+3)/(7x-5)

domain

\frac{2 x + 3}{7 x - 5}

x < \frac{5}{7} or x > \frac{5}{7}

Interval Notation

(- \infty, \frac{5}{7}) \cup (\frac{5}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{7}

The function domain

x < \frac{5}{7} or x > \frac{5}{7}

f (x) = \frac{39 x}{x ^{2} - 5 x - 14}

\frac{x + 6}{x - 6}

f (x) = \frac{( - 3 x ^{2} + 4 )}{4 x ^{2} + 5}

f (x) = \frac{lo g _{\frac{1}{2}} ( 1 )}{x ^{2} - 5 x}

f (x) = \frac{8 + x}{7 - x}

What is the domain of (2x+3)/(7x-5) ?
The domain of (2x+3)/(7x-5) is x< 5/7 \lor x> 5/7