What is the domain of f(x)=(x^2+2x-8)/(x^2-x-2) ?

The domain of f(x)=(x^2+2x-8)/(x^2-x-2) is x 2

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domain of f(x)=(x^2+2x-8)/(x^2-x-2)

domain

f (x) = \frac{x ^{2} + 2 x - 8}{x ^{2} - x - 2}

x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 1

The function domain

x < - 1 or - 1 < x < 2 or x > 2

f (x) = \frac{x - 5}{x ^{2} - 6 x + 8}

f (x) = \frac{6}{x + 3} \cdot \frac{7}{x}

f (x) = ∣ x ∣^{2} - 16

f (x) = x^{\frac{4}{5}} (x^{2} - 9)

f (x) = 1 - ln (5 x - 1)

What is the domain of f(x)=(x^2+2x-8)/(x^2-x-2) ?
The domain of f(x)=(x^2+2x-8)/(x^2-x-2) is x<-1\lor-1<x<2\lor x>2