What is the domain of f(x)=sqrt(|x|^2-16) ?

The domain of f(x)=sqrt(|x|^2-16) is x = 4

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domain of f(x)=sqrt(|x|^2-16)

domain

f (x) = ∣ x ∣^{2} - 16

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

f (x) = x^{\frac{4}{5}} (x^{2} - 9)

f (x) = 1 - ln (5 x - 1)

f (x) = \frac{( 2 x )}{( x ^{2} - 3 x + 2 )}

- \frac{1}{4} - 5

f (x) = 9 - 7 \cdot 10 - 2 x

What is the domain of f(x)=sqrt(|x|^2-16) ?
The domain of f(x)=sqrt(|x|^2-16) is x<=-4\lor x>= 4