What is the domain of f(x)=sqrt(2x+1)-4 ?

The domain of f(x)=sqrt(2x+1)-4 is x>=-1/2

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domain of f(x)=sqrt(2x+1)-4

domain

f (x) = 2 x + 1 - 4

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

(5 x - 6) (2 x^{2})

f (x) = \frac{3 x ^{2} + 6 x + 9}{x ^{2} + 4 x + 3}

f (x) = \frac{( 11 )}{x - 4}

y = \frac{4}{x ^{2} + 4} + \frac{7}{x ^{2} - 9}

f (x) = ln (x^{2} - 4) + π

What is the domain of f(x)=sqrt(2x+1)-4 ?
The domain of f(x)=sqrt(2x+1)-4 is x>=-1/2