What is the domain of f(x)=\sqrt[4]{-x^2-3x+28} ?

The domain of f(x)=\sqrt[4]{-x^2-3x+28} is -7<= x<= 4

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domain of f(x)=\sqrt[4]{-x^2-3x+28}

domain

- 7 \leq x \leq 4

Interval Notation

[- 7, 4]

Solution steps

Find non-negative values for radicals:

- 7 \leq x \leq 4

The function domain

- 7 \leq x \leq 4

f (x) = x - 4 - x^{2}

f (x) = x + x - 18

\frac{x - 1}{25 - x ^{2}}

f (x) = \frac{x ^{2} - 3 x - 28}{x + 4}

f (x) = \frac{3}{x - 2} + 2

What is the domain of f(x)=\sqrt[4]{-x^2-3x+28} ?
The domain of f(x)=\sqrt[4]{-x^2-3x+28} is -7<= x<= 4