What is the domain of f(x)=(x^2-7)/(sqrt(x^2+3x-4)) ?

The domain of f(x)=(x^2-7)/(sqrt(x^2+3x-4)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2-7)/(sqrt(x^2+3x-4))

domain

f (x) = \frac{x ^{2} - 7}{x ^{2} + 3 x - 4}

x < - 4 or x > 1

Interval Notation

(- \infty, - 4) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x > 1

f (x) = \frac{x - 8}{x ^{2} - 49}

f (x) = \frac{3 x + 9}{x ^{2} + x - 12}

f (x) = 5 \cdot 1 - x - 3

\frac{2 x + 1}{x - 5}

(\frac{- 3 x ^{2}}{2}) + \frac{225 x}{2}

What is the domain of f(x)=(x^2-7)/(sqrt(x^2+3x-4)) ?
The domain of f(x)=(x^2-7)/(sqrt(x^2+3x-4)) is x<-4\lor x>1