What is the domain of f(x)=-sqrt(((x^2))/(x-1)) ?

The domain of f(x)=-sqrt(((x^2))/(x-1)) is x=0\lor x>1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=-sqrt(((x^2))/(x-1))

domain

f (x) = - \frac{( x ^{2} )}{x - 1}

x = 0 or x > 1

Interval Notation

x = 0 \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x = 0 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x = 0 or x > 1

\frac{2 x ^{3} - x ^{2} - 18 x + 9}{x ^{2} + 4 x + 3}

f (x) = - 4 x^{2} + 16 x - 10

f (x) = \frac{\frac{1}{x}}{\frac{1}{x}}

5 x + 6 + 1 - 8 x

y = \frac{5 - x}{- 4 x + 8}

What is the domain of f(x)=-sqrt(((x^2))/(x-1)) ?
The domain of f(x)=-sqrt(((x^2))/(x-1)) is x=0\lor x>1