What is the domain of (2x^3-x^2-18x+9)/(x^2+4x+3) ?

The domain of (2x^3-x^2-18x+9)/(x^2+4x+3) is x -1

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domain of (2x^3-x^2-18x+9)/(x^2+4x+3)

domain

\frac{2 x ^{3} - x ^{2} - 18 x + 9}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

f (x) = - 4 x^{2} + 16 x - 10

f (x) = \frac{\frac{1}{x}}{\frac{1}{x}}

5 x + 6 + 1 - 8 x

y = \frac{5 - x}{- 4 x + 8}

\frac{4 x ^{2} + 1}{( - 2 x + 1 ) x}

What is the domain of (2x^3-x^2-18x+9)/(x^2+4x+3) ?
The domain of (2x^3-x^2-18x+9)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1