What is the extreme f(x)=-3(5-3x)e^{-4x} ?

The extreme f(x)=-3(5-3x)e^{-4x} is Maximum(23/12 , 9/(4e^{23/3)})

Popular >

extreme f(x)=-3(5-3x)e^{-4x}

extreme points

f (x) = - 3 (5 - 3 x) e^{- 4 x}

Maximum (\frac{23}{12}, \frac{9}{4 e ^{\frac{23}{3}}})

Solution steps

Find the critical points:

x = \frac{23}{12}

Domain of

- 3 (5 - 3 x) e^{- 4 x} : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < \frac{23}{12},

Decreasing

: \frac{23}{12} < x < \infty

Plug the extreme point

x = \frac{23}{12}

into

- 3 (5 - 3 x) e^{- 4 x} \Rightarrow y = \frac{9}{4 e ^{\frac{23}{3}}}

Maximum (\frac{23}{12}, \frac{9}{4 e ^{\frac{23}{3}}})

\frac{2 x - 5}{x ^{2} - 4}

f (x, y) = x^{2} y + 3 x y^{2}

f (x) = x^{4} + y^{4} - 4 x y + 1

f (x) = \frac{3 x - 6}{x + 2}

f (x, y) = 1 - x^{2} + 2 y^{2}

What is the extreme f(x)=-3(5-3x)e^{-4x} ?
The extreme f(x)=-3(5-3x)e^{-4x} is Maximum(23/12 , 9/(4e^{23/3)})