What is the extreme f(x)=-x^3-6x^2-9x+3 ?

The extreme f(x)=-x^3-6x^2-9x+3 is Minimum(-3,3),Maximum(-1,7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3-6x^2-9x+3

extreme points

f (x) = - x^{3} - 6 x^{2} - 9 x + 3

Minimum (- 3, 3), Maximum (- 1, 7)

Solution steps

f^{'} (x) = - 3 x^{2} - 12 x - 9

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - 3

into

- x^{3} - 6 x^{2} - 9 x + 3 : 3

Minimum (- 3, 3)

Plug

x = - 1

into

- x^{3} - 6 x^{2} - 9 x + 3 : 7

Maximum (- 1, 7)

Minimum (- 3, 3), Maximum (- 1, 7)

f (x) = x^{3} - 6 x^{2} + 3

f (x) = x^{2} + 9

\frac{4}{x + 6}

f (x, y) = 113 x + 15 y - x^{2} - 2 y^{2} + 3 x y

f (x) = - x^{3} + 6 x^{2} + 15 x + 4

What is the extreme f(x)=-x^3-6x^2-9x+3 ?
The extreme f(x)=-x^3-6x^2-9x+3 is Minimum(-3,3),Maximum(-1,7)