What is the extreme f(x,y)=18x^2-32y^2-36x-128y-110 ?

The extreme f(x,y)=18x^2-32y^2-36x-128y-110 is Saddle(1,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=18x^2-32y^2-36x-128y-110

extreme points

f (x, y) = 18 x^{2} - 32 y^{2} - 36 x - 128 y - 110

Saddle (1, - 2)

Solution steps

Find the critical points:

(1, - 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 64

D (x, y) = - 2304

Check the sign of at each critical point

Check critical point

(1, - 2) :

Saddle

Saddle (1, - 2)

y = 2 x^{2} - 8 x + 8

f (x, y) = (4 x^{2} + 10 y^{2}) e^{- y}

P (x, y) = 6 x^{2} - x y - y^{2} + y + 8 x + 2

f (x) = (x + 2)^{\frac{4}{3}}

f (x) = x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4

What is the extreme f(x,y)=18x^2-32y^2-36x-128y-110 ?
The extreme f(x,y)=18x^2-32y^2-36x-128y-110 is Saddle(1,-2)