What is the extreme f(x)=(x-8)ln(x-8) ?

The extreme f(x)=(x-8)ln(x-8) is Minimum(1/e+8,-1/e)

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extreme f(x)=(x-8)ln(x-8)

extreme points

f (x) = (x - 8) ln (x - 8)

Minimum (\frac{1}{e} + 8, - \frac{1}{e})

Solution steps

f^{'} (x) = ln (x - 8) + 1

Find intervals:

Decreasing

: 8 < x < \frac{1}{e} + 8,

Increasing

: \frac{1}{e} + 8 < x < \infty

Plug

x = \frac{1}{e} + 8

into

(x - 8) ln (x - 8) : - \frac{1}{e}

Minimum (\frac{1}{e} + 8, - \frac{1}{e})

f (x) = 2 x^{2} + y^{2} - y

f (x) = x^{3} + 6 x^{2} + 12 x + 5

f (x) = x^{4} - 98 x^{2} + 4

(x + 3)^{2} (x^{3} - x^{2})

f (x) = (x + 2)^{3} - 5

What is the extreme f(x)=(x-8)ln(x-8) ?
The extreme f(x)=(x-8)ln(x-8) is Minimum(1/e+8,-1/e)