What is the extreme f(x)=(x-8)ln(x-8) ?

The extreme f(x)=(x-8)ln(x-8) is Minimum(1/e+8,-1/e)

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extreme f(x)=(x-8)ln(x-8)

extreme

Minimum (\frac{1}{e} + 8, - \frac{1}{e})

Solution steps

f^{'} (x) = ln (x - 8) + 1

Find intervals:

Decreasing

: 8 < x < \frac{1}{e} + 8,

Increasing

: \frac{1}{e} + 8 < x < \infty

Plug

x = \frac{1}{e} + 8

into

(x - 8) ln (x - 8) : - \frac{1}{e}

Minimum (\frac{1}{e} + 8, - \frac{1}{e})

What is the extreme f(x)=(x-8)ln(x-8) ?
The extreme f(x)=(x-8)ln(x-8) is Minimum(1/e+8,-1/e)