What is the extreme f(x,y)=3x^2+y^2-xy-11x ?

The extreme f(x,y)=3x^2+y^2-xy-11x is Minimum(2,1)

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extreme f(x,y)=3x^2+y^2-xy-11x

extreme points

f (x, y) = 3 x^{2} + y^{2} - x y - 11 x

Minimum (2, 1)

Solution steps

Find the critical points:

(2, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 11

Check the sign of at each critical point

Check critical point

(2, 1) :

Minimum

Minimum (2, 1)

f (t) = (t) + 2 u (t) - 3 e^{- 2 t} u (t)

f (x) = (x - 6) e^{x}

f (x) = (x + 14) (x - 7)^{2}

f (x) = x^{3} - 48 x, - 5 \leq x \leq 5

y = 5 x^{6} - 3 x^{4} + 2 x - 9

What is the extreme f(x,y)=3x^2+y^2-xy-11x ?
The extreme f(x,y)=3x^2+y^2-xy-11x is Minimum(2,1)