What is the extreme f(x)=x^3-12x+17 ?

The extreme f(x)=x^3-12x+17 is Maximum(-2,33),Minimum(2,1)

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extreme f(x)=x^3-12x+17

extreme points

f (x) = x^{3} - 12 x + 17

Maximum (- 2, 33), Minimum (2, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 17 : 33

Maximum (- 2, 33)

Plug

x = 2

into

x^{3} - 12 x + 17 : 1

Minimum (2, 1)

Maximum (- 2, 33), Minimum (2, 1)

f (x) = x^{3} + 2 x^{2} - 20 x

e^{4 x} + e^{- x}

f (x) = x^{2} - 12 x + 8

f (x) = \frac{2 x ^{2}}{x ^{2} - 1}

f (x, y) = x^{2} + 5 x y + y^{2}

What is the extreme f(x)=x^3-12x+17 ?
The extreme f(x)=x^3-12x+17 is Maximum(-2,33),Minimum(2,1)