What is the extreme f(x)=x^3-27x+51 ?

The extreme f(x)=x^3-27x+51 is Maximum(-3,105),Minimum(3,-3)

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extreme f(x)=x^3-27x+51

extreme points

f (x) = x^{3} - 27 x + 51

Maximum (- 3, 105), Minimum (3, - 3)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 51 : 105

Maximum (- 3, 105)

Plug

x = 3

into

x^{3} - 27 x + 51 : - 3

Minimum (3, - 3)

Maximum (- 3, 105), Minimum (3, - 3)

f (x) = x^{3} - 27 x + 50

g (x) = x^{3} - 3 x + 2

f (x) = x^{3} - 3 x + 11

f (x, y) = 144 - 9 x^{2} - 16 y^{2}

f (x) = 24 x^{3} - 3 x^{4}

What is the extreme f(x)=x^3-27x+51 ?
The extreme f(x)=x^3-27x+51 is Maximum(-3,105),Minimum(3,-3)