What is the extreme f(x)=-x^2+3x^2+9x+1 ?

The extreme f(x)=-x^2+3x^2+9x+1 is Minimum(-9/4 ,-73/8)

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extreme f(x)=-x^2+3x^2+9x+1

extreme points

f (x) = - x^{2} + 3 x^{2} + 9 x + 1

Minimum (- \frac{9}{4}, - \frac{73}{8})

Solution steps

f^{'} (x) = 4 x + 9

Find intervals:

Decreasing

: - \infty < x < - \frac{9}{4},

Increasing

: - \frac{9}{4} < x < \infty

Plug

x = - \frac{9}{4}

into

- x^{2} + 3 x^{2} + 9 x + 1 : - \frac{73}{8}

Minimum (- \frac{9}{4}, - \frac{73}{8})

f (x) = \frac{t}{t - 1} (2.3)

f (x) = (x^{2} + 1) (4 x^{2} - 1)

72 y^{2} + x^{2} - x^{2} y

f (x) = x^{4} - 32 x + 3

f (x) = x^{3} - 6 x - 4

What is the extreme f(x)=-x^2+3x^2+9x+1 ?
The extreme f(x)=-x^2+3x^2+9x+1 is Minimum(-9/4 ,-73/8)