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Popular >

extreme f(x)=2x^2+18x+16

Solution

extreme points

f (x) = 2 x^{2} + 18 x + 16

Solution

Minimum (- \frac{9}{2}, - \frac{49}{2})

Solution steps

f^{'} (x) = 4 x + 18

Find intervals:

Decreasing

: - \infty < x < - \frac{9}{2},

Increasing

: - \frac{9}{2} < x < \infty

Plug

x = - \frac{9}{2}

into

2 x^{2} + 18 x + 16 : - \frac{49}{2}

Minimum (- \frac{9}{2}, - \frac{49}{2})

Popular Examples

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y = 3 x^{2} = 12 x + 11

extreme f(x)=x^3-4x^2-3x-6 extreme points

f (x) = x^{3} - 4 x^{2} - 3 x - 6

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+18x+16 ?
The extreme f(x)=2x^2+18x+16 is Minimum(-9/2 ,-49/2)