en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=4x^2+3

Solution

extreme points

f (x) = 4 x^{2} + 3

Solution

Minimum (0, 3)

Solution steps

f^{'} (x) = 8 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

4 x^{2} + 3 : 3

Minimum (0, 3)

Popular Examples

extreme f(x)=(1/12 x^3-9x+5)extreme points

f (x) = (\frac{1}{12} x^{3} - 9 x + 5)

extreme f(x)=2x^2+18x+16 extreme points

f (x) = 2 x^{2} + 18 x + 16

extreme y=3x^2=12x+11 extreme points

y = 3 x^{2} = 12 x + 11

extreme f(x)=x^3-4x^2-3x-6 extreme points

f (x) = x^{3} - 4 x^{2} - 3 x - 6

extreme f(x)= 5/(x^2+1)extreme points

f (x) = \frac{5}{x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2+3 ?
The extreme f(x)=4x^2+3 is Minimum(0,3)