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Popular >

extreme f(1)=sqrt(x+3)

Solution

extreme points

f (1) = x + 3

Solution

Minimum (- 3, 0)

Solution steps

f^{'} (x) = \frac{1}{2 x + 3}

Find intervals:

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x + 3 : 0

Minimum (- 3, 0)

Popular Examples

extreme f(x)=-5/12 x^3-5x^2-15x-6 extreme points

f (x) = - \frac{5}{12} x^{3} - 5 x^{2} - 15 x - 6

extreme y=(x^3+8)/x extreme points

y = \frac{x ^{3} + 8}{x}

extreme f(x)=2x^3+21x^2+72x-2 extreme points

f (x) = 2 x^{3} + 21 x^{2} + 72 x - 2

extreme f(x)=4cos(3x)extreme points

f (x) = 4 cos (3 x)

simplify ln(e^{(u+v)/2})-v simplify

ln (e^{\frac{u + v}{2}}) - v

Frequently Asked Questions (FAQ)

What is the extreme f(1)=sqrt(x+3) ?
The extreme f(1)=sqrt(x+3) is Minimum(-3,0)