What is the extreme f(x)=xsqrt(x+4) ?

The extreme f(x)=xsqrt(x+4) is Maximum(-4,0),Minimum(-8/3 ,-(16)/(3sqrt(3)))

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extreme f(x)=xsqrt(x+4)

extreme points

f (x) = x x + 4

Maximum (- 4, 0), Minimum (- \frac{8}{3}, - \frac{16}{3 3})

Solution steps

f^{'} (x) = \frac{3 x + 8}{2 x + 4}

Find intervals:

Decreasing

: - 4 < x < - \frac{8}{3},

Increasing

: - \frac{8}{3} < x < \infty

Plug

x = - 4

into

x x + 4 : 0

Maximum (- 4, 0)

Plug

x = - \frac{8}{3}

into

x x + 4 : - \frac{16}{3 3}

Minimum (- \frac{8}{3}, - \frac{16}{3 3})

Maximum (- 4, 0), Minimum (- \frac{8}{3}, - \frac{16}{3 3})

f (x, y) = - 2 x^{4} y^{2} + 3 x

f (x) = 2 x (18 - 2 x^{2})

(x^{2} - 1) \cdot (e^{y} - 1) + (y^{2} - 2 y + 2) e^{y}

f (x) = x x + 6

f (x, y) = x^{2} + y^{2} + 10 x - 4 y

What is the extreme f(x)=xsqrt(x+4) ?
The extreme f(x)=xsqrt(x+4) is Maximum(-4,0),Minimum(-8/3 ,-(16)/(3sqrt(3)))