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Popular >

extreme y=x^2+2x+2

Solution

extreme points

y = x^{2} + 2 x + 2

Solution

Minimum (- 1, 1)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x + 2 : 1

Minimum (- 1, 1)

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2+2x+2 ?
The extreme y=x^2+2x+2 is Minimum(-1,1)