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Popular >

extreme (x^2)/(x^2+2)

Solution

extreme points

\frac{x ^{2}}{x ^{2} + 2}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{4 x}{( x ^{2} + 2 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} + 2} : 0

Minimum (0, 0)

Popular Examples

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f (x, y) = x^{2} - 2 y^{2} + 3 x y

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f (x) = x^{2} y + x y^{2} + 4 x y - 5 y + 3

extreme f(x,y)=3x^2-5y^2 extreme points

f (x, y) = 3 x^{2} - 5 y^{2}

extreme f(x)= 4/((x-3)^2)extreme points

f (x) = \frac{4}{( x - 3 ) ^{2}}

extreme f(x)=11+7x+x^2 extreme points

f (x) = 11 + 7 x + x^{2}

Frequently Asked Questions (FAQ)

What is the extreme (x^2)/(x^2+2) ?
The extreme (x^2)/(x^2+2) is Minimum(0,0)