What is the extreme f(x)=-x^3+3x-4 ?

The extreme f(x)=-x^3+3x-4 is Minimum(-1,-6),Maximum(1,-2)

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extreme f(x)=-x^3+3x-4

extreme points

f (x) = - x^{3} + 3 x - 4

Minimum (- 1, - 6), Maximum (1, - 2)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 4 : - 6

Minimum (- 1, - 6)

Plug

x = 1

into

- x^{3} + 3 x - 4 : - 2

Maximum (1, - 2)

Minimum (- 1, - 6), Maximum (1, - 2)

f (x) = - x^{3} + 3 x - 9

f (x) = - x^{3} + 3 x - 5

f (x) = \frac{2 x + 5}{3}, (0, 5)

f (x) = \frac{( 1 )}{( 3 ) x ^{(3)} - 400 x}

What is the extreme f(x)=-x^3+3x-4 ?
The extreme f(x)=-x^3+3x-4 is Minimum(-1,-6),Maximum(1,-2)