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Popular >

extreme f(x)=(6x^2)/(x^2-9)

Solution

extreme points

f (x) = \frac{6 x ^{2}}{x ^{2} - 9}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{108 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 0

into

\frac{6 x ^{2}}{x ^{2} - 9} : 0

Maximum (0, 0)

Graph

Popular Examples

extreme f(x)=x+(49)/x+5,1<= x<= 98 extreme points

f (x) = x + \frac{49}{x} + 5, 1 \leq x \leq 98

extreme f(x)=((x+2))/(x^2-x-6)extreme points

f (x) = \frac{( x + 2 )}{x ^{2} - x - 6}

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g (y) = 4 - y^{2}, - 2 \leq y \leq 1

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f (x) = \frac{( x ^{2} - 8 )}{x + 3}

extreme y= 3/(-(x-4)^2-1)extreme points

y = \frac{3}{- ( x - 4 ) ^{2} - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(6x^2)/(x^2-9) ?
The extreme f(x)=(6x^2)/(x^2-9) is Maximum(0,0)