What is the extreme g(y)=4-y^2,-2<= y<= 1 ?

The extreme g(y)=4-y^2,-2<= y<= 1 is Minimum(-2,0),Maximum(0,4),Minimum(1,3)

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extreme g(y)=4-y^2,-2<= y<= 1

extreme points

g (y) = 4 - y^{2}, - 2 \leq y \leq 1

Minimum (- 2, 0), Maximum (0, 4), Minimum (1, 3)

Solution steps

Find the critical points:

y = - 2, y = 0, y = 1

Domain of

4 - y^{2}, - 2 \leq y \leq 1 : - 2 \leq y \leq 1

Find intervals:

Increasing

: - 2 < y < 0,

Decreasing

: 0 < y < 1

Plug the extreme point

x = - 2

into

4 - y^{2} \Rightarrow y = 0

Minimum (- 2, 0)

Plug the extreme point

x = 0

into

4 - y^{2} \Rightarrow y = 4

Maximum (0, 4)

Plug the extreme point

x = 1

into

4 - y^{2} \Rightarrow y = 3

Minimum (1, 3)

Minimum (- 2, 0), Maximum (0, 4), Minimum (1, 3)

f (x) = \frac{( x ^{2} - 8 )}{x + 3}

y = \frac{3}{- ( x - 4 ) ^{2} - 1}

f (x y) = 2 x^{2} + 2 y^{2} + 4 x y - 8 x + 20

f (x) = ln (3 - ln (x))

f (x) = 12 x^{2} - 2 x^{3}

What is the extreme g(y)=4-y^2,-2<= y<= 1 ?
The extreme g(y)=4-y^2,-2<= y<= 1 is Minimum(-2,0),Maximum(0,4),Minimum(1,3)