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Popular >

extreme y= 3/(-(x-4)^2-1)

Solution

extreme points

y = \frac{3}{- ( x - 4 ) ^{2} - 1}

Solution

Minimum (4, - 3)

Solution steps

f^{'} (x) = - \frac{3 ( - 2 x + 8 )}{( - x ^{2} + 8 x - 17 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

\frac{3}{- ( x - 4 ) ^{2} - 1} : - 3

Minimum (4, - 3)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y= 3/(-(x-4)^2-1) ?
The extreme y= 3/(-(x-4)^2-1) is Minimum(4,-3)