What is the extreme S(u,t)=(u+u^0)/2*t ?

The extreme S(u,t)=(u+u^0)/2*t is Saddle(-1,0)

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extreme S(u,t)=(u+u^0)/2*t

extreme points

S (u, t) = \frac{u + u ^{0}}{2} \cdot t

Saddle (- 1, 0)

Solution steps

Find the critical points:

(- 1, 0)

\frac{\partial ^{2} f}{\partial u ^{2}} = 0

D (u, t) = - \frac{1}{4}

Check the sign of at each critical point

Check critical point

(- 1, 0) :

Saddle

Saddle (- 1, 0)

f (x) = (x^{2} + 1) e^{x}

f (x, y) = 2 x y^{3} - 2 x^{2} y

f (x y) = e^{- y} (x^{2} + y^{2})

f (x) = x (19 - 37 + 2 x) (\frac{37}{2} - x)

y = x^{2} (x^{2} - 5)

What is the extreme S(u,t)=(u+u^0)/2*t ?
The extreme S(u,t)=(u+u^0)/2*t is Saddle(-1,0)