What is the extreme f(x)=x^3-6x^2+9x+10 ?

The extreme f(x)=x^3-6x^2+9x+10 is Maximum(1,14),Minimum(3,10)

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extreme f(x)=x^3-6x^2+9x+10

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 10

Maximum (1, 14), Minimum (3, 10)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 10 : 14

Maximum (1, 14)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 10 : 10

Minimum (3, 10)

Maximum (1, 14), Minimum (3, 10)

4 x + 1

f (x) = 2 x^{- 3} - x^{- 2}

f (x) = \frac{x ^{6}}{6} - ln (x)

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 6, - 1 \leq x \leq 2

f (x) = cos (x) - 5 x, 0 \leq x \leq 4 π

What is the extreme f(x)=x^3-6x^2+9x+10 ?
The extreme f(x)=x^3-6x^2+9x+10 is Maximum(1,14),Minimum(3,10)