What is the extreme f(x,y)=1+xy-x-y ?

The extreme f(x,y)=1+xy-x-y is Saddle(1,1)

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extreme f(x,y)=1+xy-x-y

extreme points

f (x, y) = 1 + x y - x - y

Saddle (1, 1)

Solution steps

Find the critical points:

(1, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(1, 1) :

Saddle

Saddle (1, 1)

f (x) = 8 x + 11 x^{\frac{8}{11}}

f (x, y) = x - 2 y g (x, y) = x^{2} + y^{2} = 25

f (x) = x^{3} + x^{2} y - y^{2} - 4 y

y = x^{\frac{4}{5}} (x - 1)

f (x) = \frac{( x ^{2} - 11 )}{x + 6}

What is the extreme f(x,y)=1+xy-x-y ?
The extreme f(x,y)=1+xy-x-y is Saddle(1,1)