What is the extreme f(x)=-x-x^2(1+sqrt(2)) ?

The extreme f(x)=-x-x^2(1+sqrt(2)) is Maximum(-(sqrt(2)-1)/2 ,(sqrt(2)-1)/4)

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extreme f(x)=-x-x^2(1+sqrt(2))

extreme points

f (x) = - x - x^{2} (1 + 2)

Maximum (- \frac{2 - 1}{2}, \frac{2 - 1}{4})

Solution steps

f^{'} (x) = - 1 - 2 (1 + 2) x

Find intervals:

Increasing

: - \infty < x < - \frac{2 - 1}{2},

Decreasing

: - \frac{2 - 1}{2} < x < \infty

Plug

x = - \frac{2 - 1}{2}

into

- x - x^{2} (1 + 2) : \frac{2 - 1}{4}

Maximum (- \frac{2 - 1}{2}, \frac{2 - 1}{4})

f (x) = 64 - x^{2}

f (x, y) = x y - 4 y - 16 x + 64

y = cos (x)

2 x^{2} + 24 x - 6

f (x, y) = ((\frac{( 1 - x )}{x}) y)

What is the extreme f(x)=-x-x^2(1+sqrt(2)) ?
The extreme f(x)=-x-x^2(1+sqrt(2)) is Maximum(-(sqrt(2)-1)/2 ,(sqrt(2)-1)/4)