What is the extreme f(x)= 1/3 x^3+2x^2-5x-4 ?

The extreme f(x)= 1/3 x^3+2x^2-5x-4 is Maximum(-5, 88/3),Minimum(1,-20/3)

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extreme f(x)= 1/3 x^3+2x^2-5x-4

extreme points

f (x) = \frac{1}{3} x^{3} + 2 x^{2} - 5 x - 4

Maximum (- 5, \frac{88}{3}), Minimum (1, - \frac{20}{3})

Solution steps

f^{'} (x) = x^{2} + 4 x - 5

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 5

into

\frac{1}{3} x^{3} + 2 x^{2} - 5 x - 4 : \frac{88}{3}

Maximum (- 5, \frac{88}{3})

Plug

x = 1

into

\frac{1}{3} x^{3} + 2 x^{2} - 5 x - 4 : - \frac{20}{3}

Minimum (1, - \frac{20}{3})

Maximum (- 5, \frac{88}{3}), Minimum (1, - \frac{20}{3})

y = x^{2} - 11 x + 30

f (x) = x^{2} - 3 x y - y^{2}

f (x, y) = 4^{x - y - 7 x y} + 9 y^{2}

f (x) = x^{4} - 6 x^{2} + 2 x + 3

f (x, y) = (\frac{2}{6 ^{- x^{2} - y^{2} + 2}})

What is the extreme f(x)= 1/3 x^3+2x^2-5x-4 ?
The extreme f(x)= 1/3 x^3+2x^2-5x-4 is Maximum(-5, 88/3),Minimum(1,-20/3)