What is the extreme f(x)=((5x^4)/(ln(x))) ?

The extreme f(x)=((5x^4)/(ln(x))) is Minimum(\sqrt[4]{e},20e)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=((5x^4)/(ln(x)))

extreme points

f (x) = (\frac{5 x ^{4}}{ln ( x )})

Minimum (4 e, 20 e)

Solution steps

f^{'} (x) = \frac{5 ( 4 x ^{3} ln ( x ) - x ^{3} )}{ln ^{2} ( x )}

Find intervals:

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < 4 e,

Increasing

: 4 e < x < \infty

Plug

x = 4 e

into

\frac{5 x ^{4}}{ln ( x )} : 20 e

Minimum (4 e, 20 e)

f (x) = - (\frac{4}{x ^{2}}), (- 3, - 1)

f (x) = 4 - x^{3} + 5 x

f (x) = 2 x^{3} - 6 x + 11

f (x) = sin (5 x), 0 \leq x \leq \frac{2 π}{5}

y = 16 x^{4} + 64 x^{3}

What is the extreme f(x)=((5x^4)/(ln(x))) ?
The extreme f(x)=((5x^4)/(ln(x))) is Minimum(\sqrt[4]{e},20e)