What is the extreme f(x,y)=e^{15xy} ?

The extreme f(x,y)=e^{15xy} is Saddle(0,0)

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extreme f(x,y)=e^{15xy}

extreme points

f (x, y) = e^{15 x y}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 225 e^{15 x y} x^{2}

D (x, y) = - 6750 e^{30 x y} x y - 225 e^{30 x y}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 9 x^{2} + 3 [- 1.2]

f (x) = - 2 x^{3} - 13

f (x) = 9 - 4 x - 3 x^{2}, - 2 \leq x \leq 1

f (x) = 3 x^{2} + 12 x - 9

f (x) = 395 x^{2} - 3160 x^{3}

What is the extreme f(x,y)=e^{15xy} ?
The extreme f(x,y)=e^{15xy} is Saddle(0,0)