What is the extreme f(x)=2x^3-24x+6 ?

The extreme f(x)=2x^3-24x+6 is Maximum(-2,38),Minimum(2,-26)

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extreme f(x)=2x^3-24x+6

extreme points

f (x) = 2 x^{3} - 24 x + 6

Maximum (- 2, 38), Minimum (2, - 26)

Solution steps

f^{'} (x) = 6 x^{2} - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

2 x^{3} - 24 x + 6 : 38

Maximum (- 2, 38)

Plug

x = 2

into

2 x^{3} - 24 x + 6 : - 26

Minimum (2, - 26)

Maximum (- 2, 38), Minimum (2, - 26)

f (x) = \frac{16 ( x + 3 )}{x ^{4}}

f (x y) = x^{2} y - x - x y^{2} + y

w^{4} - 55 w^{2} + 1600

f (x) = \frac{- x ^{2}}{x ^{2} - 4}

y = \frac{x}{x ^{2} + 3}

What is the extreme f(x)=2x^3-24x+6 ?
The extreme f(x)=2x^3-24x+6 is Maximum(-2,38),Minimum(2,-26)