What is the extreme y=-0.05x^2+50x-600 ?

The extreme y=-0.05x^2+50x-600 is Maximum(500,11900)

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extreme y=-0.05x^2+50x-600

extreme points

y = - 0.05 x^{2} + 50 x - 600

Maximum (500, 11900)

Solution steps

f^{'} (x) = - 0.1 x + 50

Find intervals:

Increasing

: - \infty < x < 500,

Decreasing

: 500 < x < \infty

Plug

x = 500

into

- 0.05 x^{2} + 50 x - 600 : 11900

Maximum (500, 11900)

g (x) = - 4 x^{3} - 66 x^{2} - 360 x + 7

f (x) = 4 sin (x) cos (x) + 12

x (57 - x^{2})

f (x) = 2 x^{3} + 6 x^{2} - 18 x + 7

f (x) = 2 x^{3} + 6 x^{2} - 18 x + 6

What is the extreme y=-0.05x^2+50x-600 ?
The extreme y=-0.05x^2+50x-600 is Maximum(500,11900)