What is the extreme f(x,y)=3x^2+2y^2-18x+8y ?

The extreme f(x,y)=3x^2+2y^2-18x+8y is Minimum(3,-2)

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extreme f(x,y)=3x^2+2y^2-18x+8y

extreme points

f (x, y) = 3 x^{2} + 2 y^{2} - 18 x + 8 y

Minimum (3, - 2)

Solution steps

Find the critical points:

(3, - 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = 4

D (x, y) = 24

Check the sign of at each critical point

Check critical point

(3, - 2) :

Minimum

Minimum (3, - 2)

e^{4 x^{2} + 2 y^{2} - 24 x}

f (x) = x^{3} - 3 x^{2} + 9 x + 1

f (x) = - \frac{1}{3} x^{3} + 2 x^{2} + 12 x + 28

f (x) = - 0.015 x^{2} + 1.22 x - 7.2

f (x) = 8 - x

What is the extreme f(x,y)=3x^2+2y^2-18x+8y ?
The extreme f(x,y)=3x^2+2y^2-18x+8y is Minimum(3,-2)