What is the extreme f(x)=-0.015x^2+1.22x-7.2 ?

The extreme f(x)=-0.015x^2+1.22x-7.2 is Maximum(122/3 ,17.60666…)

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extreme f(x)=-0.015x^2+1.22x-7.2

extreme points

f (x) = - 0.015 x^{2} + 1.22 x - 7.2

Maximum (\frac{122}{3}, 17.60666 \dots)

Solution steps

f^{'} (x) = - 0.03 x + 1.22

Find intervals:

Increasing

: - \infty < x < \frac{122}{3},

Decreasing

: \frac{122}{3} < x < \infty

Plug

x = \frac{122}{3}

into

- 0.015 x^{2} + 1.22 x - 7.2 : 17.60666 \dots

Maximum (\frac{122}{3}, 17.60666 \dots)

f (x) = 8 - x

f (x) = 6 + 81 x - 3 x^{3}, 0 \leq x \leq 4

f (x) = \frac{x ^{2} + 69}{x + 10}

\frac{t ^{2}}{t + 3}

f (x) = x^{3} - 10 x + 25 x - 2

What is the extreme f(x)=-0.015x^2+1.22x-7.2 ?
The extreme f(x)=-0.015x^2+1.22x-7.2 is Maximum(122/3 ,17.60666…)