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Popular >

extreme y=ln(x)+x^2

Solution

extreme points

y = ln (x) + x^{2}

Solution

None

Solution steps

f^{'} (x) = \frac{1}{x} + 2 x

Find intervals:

None

None

Popular Examples

extreme f(x)=2x^2-8x+1 extreme points

f (x) = 2 x^{2} - 8 x + 1

extreme f(x)=4.5-x-0.25y extreme points

f (x) = 4.5 - x - 0.25 y

extreme f(x)=((x-6))/e extreme points

f (x) = \frac{( x - 6 )}{e}

extreme f(x)= 2/9 x^3+2x^2-2 extreme points

f (x) = \frac{2}{9} x^{3} + 2 x^{2} - 2

extreme f(x)=x(40-2x)^2 extreme points

f (x) = x (40 - 2 x)^{2}

Frequently Asked Questions (FAQ)

What is the extreme y=ln(x)+x^2 ?
The extreme y=ln(x)+x^2 is None