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Popular >

extreme y=x^2+(16)/x

Solution

extreme points

y = x^{2} + \frac{16}{x}

Solution

Minimum (2, 12)

Solution steps

f^{'} (x) = 2 x - \frac{16}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{2} + \frac{16}{x} : 12

Minimum (2, 12)

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2+(16)/x ?
The extreme y=x^2+(16)/x is Minimum(2,12)