What is the extreme f(x)=2x^3-3x^2-252x ?

The extreme f(x)=2x^3-3x^2-252x is Maximum(-6,972),Minimum(7,-1225)

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extreme f(x)=2x^3-3x^2-252x

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 252 x

Maximum (- 6, 972), Minimum (7, - 1225)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 252

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 6

into

2 x^{3} - 3 x^{2} - 252 x : 972

Maximum (- 6, 972)

Plug

x = 7

into

2 x^{3} - 3 x^{2} - 252 x : - 1225

Minimum (7, - 1225)

Maximum (- 6, 972), Minimum (7, - 1225)

y = 2 x^{3} + a x^{2} - 12 x - 4, x = 1

4 a p + 50 p - 9 p^{2} - \frac{1}{10} a^{2} p - 110

2 x^{3} + 5 x^{2} + 5 y^{3} - 5 y^{2} + 10

f (x, y) = x^{3} + 3 x^{2} + 6 x y + y^{2}

\frac{( 2 x + 1 )}{( e ^{x^{2}} )}

What is the extreme f(x)=2x^3-3x^2-252x ?
The extreme f(x)=2x^3-3x^2-252x is Maximum(-6,972),Minimum(7,-1225)