What is the extreme f(x)=x^4-242x^2-5 ?

The extreme f(x)=x^4-242x^2-5 is Minimum(-11,-14646),Maximum(0,-5),Minimum(11,-14646)

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extreme f(x)=x^4-242x^2-5

extreme points

f (x) = x^{4} - 242 x^{2} - 5

Minimum (- 11, - 14646), Maximum (0, - 5), Minimum (11, - 14646)

Solution steps

f^{'} (x) = 4 x^{3} - 484 x

Find intervals:

Decreasing

: - \infty < x < - 11,

Increasing

: - 11 < x < 0,

Decreasing

: 0 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = - 11

into

x^{4} - 242 x^{2} - 5 : - 14646

Minimum (- 11, - 14646)

Plug

x = 0

into

x^{4} - 242 x^{2} - 5 : - 5

Maximum (0, - 5)

Plug

x = 11

into

x^{4} - 242 x^{2} - 5 : - 14646

Minimum (11, - 14646)

Minimum (- 11, - 14646), Maximum (0, - 5), Minimum (11, - 14646)

f (x) = 20 x - 10 x - 2

2 x^{3} + 6 x^{2} - 90 x

F (x, y) = 6 - 3 x - 2 y

f (x) = x^{3} - 2 x^{2} - 15 x + 1

f (x) = x^{4} - 242 x^{2} + 7

What is the extreme f(x)=x^4-242x^2-5 ?
The extreme f(x)=x^4-242x^2-5 is Minimum(-11,-14646),Maximum(0,-5),Minimum(11,-14646)