What is the extreme f(x)=x^3-2x^2-15x+1 ?

The extreme f(x)=x^3-2x^2-15x+1 is Maximum(-5/3 , 427/27),Minimum(3,-35)

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extreme f(x)=x^3-2x^2-15x+1

extreme points

f (x) = x^{3} - 2 x^{2} - 15 x + 1

Maximum (- \frac{5}{3}, \frac{427}{27}), Minimum (3, - 35)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 15

Find intervals:

Increasing

: - \infty < x < - \frac{5}{3},

Decreasing

: - \frac{5}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - \frac{5}{3}

into

x^{3} - 2 x^{2} - 15 x + 1 : \frac{427}{27}

Maximum (- \frac{5}{3}, \frac{427}{27})

Plug

x = 3

into

x^{3} - 2 x^{2} - 15 x + 1 : - 35

Minimum (3, - 35)

Maximum (- \frac{5}{3}, \frac{427}{27}), Minimum (3, - 35)

f (x) = x^{4} - 242 x^{2} + 7

f (x, y) = x^{3} y + 4 x y^{2}

\frac{( x - 2 ) ( 3 - x )}{x ^{2}}

- x^{(2)} - 9

f (x, y) = e^{l n (x^{2} + y^{2})}

What is the extreme f(x)=x^3-2x^2-15x+1 ?
The extreme f(x)=x^3-2x^2-15x+1 is Maximum(-5/3 , 427/27),Minimum(3,-35)