What is the extreme f(x)=-13/9 x^2+8/3 x^2+37/10 ?

The extreme f(x)=-13/9 x^2+8/3 x^2+37/10 is Minimum(0, 37/10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-13/9 x^2+8/3 x^2+37/10

extreme points

f (x) = - \frac{13}{9} x^{2} + \frac{8}{3} x^{2} + \frac{37}{10}

Minimum (0, \frac{37}{10})

Solution steps

f^{'} (x) = \frac{22 x}{9}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

- \frac{13}{9} x^{2} + \frac{8}{3} x^{2} + \frac{37}{10} : \frac{37}{10}

Minimum (0, \frac{37}{10})

\frac{( x - 4 )}{x ^{2}}

f (x) = \frac{2 x - 6}{x ^{2} + 7 - 4}

f (x) = (5 + x) + (1000 + 100 x)

f (x) = - (\frac{x}{3})^{3} + 2 x^{2} + 12 x + 1

y = 5 + 6 x - 8 x^{3}

What is the extreme f(x)=-13/9 x^2+8/3 x^2+37/10 ?
The extreme f(x)=-13/9 x^2+8/3 x^2+37/10 is Minimum(0, 37/10)