What is the extreme y=15xe^{-x} ?

The extreme y=15xe^{-x} is Maximum(1,(15)/e)

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extreme y=15xe^{-x}

extreme points

y = 15 x e^{- x}

Maximum (1, \frac{15}{e})

Solution steps

Find the critical points:

x = 1

Domain of

15 x e^{- x} : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug the extreme point

x = 1

into

15 x e^{- x} \Rightarrow y = \frac{15}{e}

Maximum (1, \frac{15}{e})

f (x) = x^{2} + 6

f (x) = 6 x^{2} + 1 - x, 0 \leq x \leq 3

f (x) = x^{2} - x - 5

5 x^{3} + 67.5 x^{2} + 2 x + 10

f (x) = 25 x^{2} - x^{3}