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Popular >

extreme g(x)=x^2-10x+27

Solution

extreme points

g (x) = x^{2} - 10 x + 27

Solution

Minimum (5, 2)

Solution steps

f^{'} (x) = 2 x - 10

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

x^{2} - 10 x + 27 : 2

Minimum (5, 2)

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Frequently Asked Questions (FAQ)

What is the extreme g(x)=x^2-10x+27 ?
The extreme g(x)=x^2-10x+27 is Minimum(5,2)